UC ignition wiring
#1 _ucstephan_
Posted 27 January 2020 - 10:52 AM
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#2
Posted 27 January 2020 - 11:24 AM
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#3
Posted 27 January 2020 - 12:04 PM
Holden didn't use ballast resistors for the coil, they used a resistance wire that achieved a similar result. However, during crank the coil received a full 12V (no resistance) connection to counter the voltage drop and ensure good spark. So there would have originally been two wires - a pink one from the ON position and a yellow one from the START position, and these are connected together at the coil end. This trips up a lot of people doing conversions.
If you are running a 9V coil you need to either use a resistance wire and replicate the original loom or install a ballast resistor. If you are running a 12V coil you can simply bridge the two terminals at the ignition switch and run a single wire.
#4 _ucstephan_
Posted 27 January 2020 - 12:07 PM
Thanks for that, my old man and I worked it out about a minute before you replied haha this is the first time I've done any real work with wiring so it's a case of getting my head around how to read a diagram and all that goes with wiring, thanks for your help!Holden didn't use ballast resistors for the coil, they used a resistance wire that achieved a similar result. However, during crank the coil received a full 12V (no resistance) connection to counter the voltage drop and ensure good spark. So there would have originally been two wires - a pink one from the ON position and a yellow one from the START position, and these are connected together at the coil end. This trips up a lot of people doing conversions.
If you are running a 9V coil you need to either use a resistance wire and replicate the original loom or install a ballast resistor. If you are running a 12V coil you can simply bridge the two terminals at the ignition switch and run a single wire.
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