any idea how fast my car could go?

i know there are HEAPS of variables in how fast a car can go but i was wondering if anyone can give me a ROUGH idea of what kinda times i could get? its a 1972 LJ.
HP block
bore size: 3.665 inches
capacity: 190 cubic inches
stroke: standard 186
compression ratio: 9.2:1
balanced
pistons: ACL flat tops
rings: ACL moly
starfire rods
ARP rod bolts
ACL bearings
LC XU1 spec cam
powerboss hydrolic lifters
street terra roller rockers
ACL gaskets
350 4 brl holley
celica 5 spd

like i said i realise how hard it would be to answer such a question, its just that i'm bored and always wondered how hard it could go. (and to anyone who is thinking "drive it and find out" i would but its still a good few months off being on the road )

mate, mine in its current spec runs out of steam around the 100mph (160km/h) mark (still climbing but very slowly), if you couldent get 120mph (200km/h) from that i'd be suprised.. what diff gears are you running???

As mentioned above, what diff gears... To give you an example, my UC with a HP block, 4speed, 3.08:1 diff, very similar spec motor to yours (slightly more agressive cam and lots of headwork) runs a 14.8 1/4 mile, ive taken it past 160km/h (100mph) and had plenty of room for more.... If your asking about top speed, i rekon close to 200km/h with the same diff ratio as mine, but again, it all depends on conditions!

Im running an XU-1 Bathurst cam (what they used in the race cars), Hypatec flat top pistons and my compression is about 10.6:1. Mine's a 186 bore, i'm running the same rods, bearings and piston rings as you, same carby, same gaskets and same rockers...

I would estimate you would be at least in the 15second 1/4 mile times... If your diff ratio is less than mine, probably close to 14's, if your running 3.9:1 diff, well and truly 14's...
Keith

This is a formula I stumbled across over 15 years ago.

V = ( cube root ) ( 59489 x Kw ) / ( Cd x A )

Kw = Engine output in Kw
Cd = drag coeffient
A = cross sectional area of vehicle in Sq metres.

So for a 100 Kw LJ ( which has a Cd of around 0.45 ) the formulae works out as:

( cube root ) ( 59489 x 100 ) / ( 0.45 x A )

I don't have the cross sectional area of an LJ handy, so somebody else can fill in the blank.