
measuring PCD
#1
_nibbsy_
Posted 18 September 2006 - 11:02 PM
They are 15" in diameter and i think they might be commodore pattern cos they came with hub caps that look they are off a VR and i'm pretty sure HQ would have never had a set of 15" back in the day.
I was after a way to measure the PCD accurately and check out if they are commo or HQ.
Could someone also tell me which one is which, 120.5 is HQ or commo and if 120.9 is commo or HQ.
Thanks heaps
nibbsy
#2
Posted 19 September 2006 - 08:19 AM
HQ/WB is 4 3/4" (120.8mm")
#3
Posted 19 September 2006 - 12:40 PM
HQ/Chev is actually 120.65mm or 4 3/4"Commodore is 120mm
HQ/WB is 4 3/4" (120.8mm")
#4
_devilsadvocate_
Posted 19 September 2006 - 01:07 PM
Finding the centre of the wheel or measuring to it is not always easy.
Using some basic year 9 trigonometry:
The pcd of the wheel in inches will be (dist bw studs in cm/ 1.49)
pcd(in)= adj studs (cm)/1.49 (for five studs)
or dist bw studs (cm) = 1.49 x pcd
For a torrie wheel 4.25in(or is it 4.24) pcd, dist bw studs = 1.49 x 4.25 = 6.35cm
Hope this is of help
Edited by devilsadvocate, 19 September 2006 - 01:17 PM.
#5
_HB1200_
Posted 19 September 2006 - 04:12 PM
HB1200
#6
_nibbsy_
Posted 19 September 2006 - 10:58 PM
I'm flat out remembering year 9 let alone trigonometry from it!!!Using some basic year 9 trigonometry

Thanks for the replies guys, i was thinking of just taking one down to a tyre shop and seeing if they can suss it out for me.
Cheers again
nibbsy
#7
_devilsadvocate_
Posted 20 September 2006 - 12:10 AM
Thats why I gave you the formula for pcd from stud separation, I only mentioned it being yr9 maths(which it is) as there would be those on this forum that would waste time challenging that it was plucked out of thin air etcI'm flat out remembering year 9 let alone trigonometry from it!!!Using some basic year 9 trigonometry
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Anyway understand the prob, you have a rim with the holes for the studs and you have to be able to measure to near to an accuracy of 0.7mm and have difficulty actually deciding exactly on the centre of the holes.
One way to do this with the holes is measure the distance of the closest edge of one hole to the closest edge of the an adjacent hole and measure the distance of the furthest edge to an adjacent furthest edge, add the two together and divide by 2.
Id be confident of a correct answer using a mm ruler, but would be best done with a vernier.
Id imagine that a tyre shop perhaps might have something to help out.
#8
Posted 20 September 2006 - 12:17 AM
One way to do this with the holes is measure the distance of the closest edge of one hole to the closest edge of the an adjacent hole and measure the distance of the furthest edge to an adjacent furthest edge, add the two together and divide by 2.
Id be confident of a correct answer using a mm ruler, but would be best done with a vernier.
or you could save yourself time by measuring to the closest side of 1 hole, and the furtherest side of the other........
#9
_devilsadvocate_
Posted 20 September 2006 - 12:34 AM

#10
Posted 20 September 2006 - 12:39 AM
looks like your the latter this time

#11
_devilsadvocate_
Posted 20 September 2006 - 01:02 AM

Edited by devilsadvocate, 20 September 2006 - 01:09 AM.
#12
Posted 20 September 2006 - 01:08 AM


I suppose it depends on how much you want to debate it......
Edited by makka, 20 September 2006 - 01:09 AM.
#13
_devilsadvocate_
Posted 20 September 2006 - 07:46 AM
Hell no...........be a good essay discussion topic for some of our readers still at school though.I suppose it depends on how much you want to debate it......
Edited by devilsadvocate, 20 September 2006 - 07:47 AM.
#14
Posted 20 September 2006 - 08:44 AM
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